Mik*_*ike 9
您可以创建结构来模仿您的json结构,然后解码您的json.
package main
import (
"bytes"
"encoding/json"
"fmt"
"log"
)
type Example struct {
Type string `json:"type,omitempty"`
Subsets []Subset `json:"subsets,omitempty"`
}
type Subset struct {
Addresses []Address `json:"addresses,omitempty"`
}
type Address struct {
IP string `json:"IP,omitempty"`
}
func main() {
m := []byte(`{"type":"example","data": {"name": "abc","labels": {"key": "value"}},"subsets": [{"addresses": [{"ip": "192.168.103.178"}],"ports": [{"port": 80}]}]}`)
r := bytes.NewReader(m)
decoder := json.NewDecoder(r)
val := &Example{}
err := decoder.Decode(val)
if err != nil {
log.Fatal(err)
}
// If you want to read a response body
// decoder := json.NewDecoder(res.Body)
// err := decoder.Decode(val)
// Subsets is a slice so you must loop over it
for _, s := range val.Subsets {
// within Subsets, address is also a slice
// then you can access each IP from type Address
for _, a := range s.Addresses {
fmt.Println(a.IP)
}
}
}
192.168.103.178
通过将其解码为结构,您可以遍历任何切片,而不是将自己限制为一个IP
这里的例子:
- 新代码@ https://play.golang.org/p/sWA9qBWljA完全返回`192.168.103.178`,检查出来;) (2认同)