golang 解析xml文件

发送soap请求返回的xml

* response.xml

<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope
    xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/"
    xmlns:ns1="http://dmdelivery.com/webservice/">
  <SOAP-ENV:Body>
    <ns1:addRecipientResponse>
      <addRecipient_result>
	<status>DUPLICATE</status>
	<statusMsg>Duplicate recipient</statusMsg>
	<id>2390018</id>
      </addRecipient_result>
    </ns1:addRecipientResponse>
  </SOAP-ENV:Body>
</SOAP-ENV:Envelope>

* response.go

package main

import (
	"encoding/xml"
	"fmt"
	"io/ioutil"
	"os"
)

type Envelope struct {
	XMLName xml.Name `xml:"Envelope"`
	Body Body `xml:"Body"`
}

type Body struct {
	XMLName xml.Name `xml:"Body"`
	AddRecipientResponse AddRecipientResponse `xml:"addRecipientResponse"`
}

type AddRecipientResponse struct {
	XMLName xml.Name `xml:addRecipientResponse`
	AddRecipientResult AddRecipientResult `xml:addRecipient_result`
}

type AddRecipientResult struct {
	XMLName xml.Name `xml:"addRecipient_result"`
	Status string `xml:"status"`
	StatusMsg string `xml:"statusMsg"`
	ID int `xml:"id"`
}

func main() {
	file, err := os.Open("response.xml")
	if err != nil {
		fmt.Println(err.Error())
		return
	}
	defer file.Close()

	data, err := ioutil.ReadAll(file)
	if err != nil {
		fmt.Println(err.Error())
		return
	}

	v := Envelope{}
	err = xml.Unmarshal(data, &v)
	if err != nil {
		fmt.Println(err.Error())
		return
	}
	fmt.Println(v.Body.AddRecipientResponse.AddRecipientResult.Status)
	fmt.Println(v.Body.AddRecipientResponse.AddRecipientResult.StatusMsg)
	fmt.Println(v.Body.AddRecipientResponse.AddRecipientResult.ID)
}

* test:

$ go run response.go
DUPLICATE
Duplicate recipient
2390018