go 中Interface{} 转int

        go中interface类型很好用，但是有时候用了就没办法作为键值了  这点就比较头痛了，这里介绍一种转换方法，非常好用

​
func GetInterfaceToInt(t1 interface{}) int {
	var t2 int
	switch t1.(type) {
	case uint:
		t2 = int(t1.(uint))
		break
	case int8:
		t2 = int(t1.(int8))
		break
	case uint8:
		t2 = int(t1.(uint8))
		break
	case int16:
		t2 = int(t1.(int16))
		break
	case uint16:
		t2 = int(t1.(uint16))
		break
	case int32:
		t2 = int(t1.(int32))
		break
	case uint32:
		t2 = int(t1.(uint32))
		break
	case int64:
		t2 = int(t1.(int64))
		break
	case uint64:
		t2 = int(t1.(uint64))
		break
	case float32:
		t2 = int(t1.(float32))
		break
	case float64:
		t2 = int(t1.(float64))
		break
	case string:
		t2, _ = strconv.Atoi(t1.(string))
		break
	default:
		t2 = t1.(int)
		break
	}
	return t2
}

​